Zeroes of Functions

Hello,

The zeroes of a function are known by many names. Some of these names include the x-intercept, x value. However, they all boil down to one thing. Solving for x. In a function f(x), if f(x) = x - 1, the zero would be 1, as when one solves for x, by adding a 1 to both sides, one can isolate the x. Zeroes are a key unit to solving any math equation, and are often asked for in many math problems inside and outside the classroom. Finding the zeroes is incorporated in algebra, calculus, math analysis, and geometry, and trigonometry. Pretty much every aspect of math.

Thanks,

Kaili Chiu

Piecewise Functions

Hi,

Today in Mathland, I learned about Piecewise functions. The funny thing about these is that they are multiple functions put together in the Cartesian Plane. We found the domain of the functions, and used it to plot each of them. Later, we discovered whether they were continuous or discontinuous. This can be found just by looking at the visuals of the plotted functions. If it is discontinuous, we would state where and at which points it was discontinuous. In addition, we also learned how to plot and identify [(x)] functions.

Thanks,
Kaili Chiu

Superhero Functions

Hi,

In the assignment for the f(x) men, we used specific functions to complete missions. This project allowed us to learn about transformations in functions, and how they are represented on the Cartesian plane. We used specific functions as superheroes to defeat the evildoers by transforming the function so that the function would hit certain points where the targets were. In certain graphs, we had to combine heroes and eliminate in the least amount of moves possible, and in others, we could only move along a certain axis. Some of these functions were 2^x, linear functions, parabolas, cubic functions, absolute value functions. The hardest mission was "The Outer Demon - Magic Foxes", where we had to finish the mission using negative functions. Overall, this was an interesting assignment that allowed us to understand transformations of functions.

Thanks,

Kaili Chiu